Conor McGregor Says He’s Back Headlining UFC 200, Dana White Says He’s Not

Conor McGregor UFC
Dan Flynn

Conor McGregor says he’s back on UFC 200 after his refusal to commit to media events forced him off the card last week. Dana White says no he’s not.

UFC.com remained mum on an announcement of any kind. But after a lackluster performance by Jon Jones this weekend in a decision victory over Ovince St. Preux, the notion of a Jones-Daniel Cormier rematch to top the marquee on the promotion’s signature 2016 card looked less appealing. So, when King Conor said his name again rules the pay-per view, why would anyone doubt him?

But UFC President Dana White insists he doesn’t know why McGregor posted this statement.

Dana White in Boston Jan 2015

“All the media keeps asking me that,” he told TMZ. “I feel like the scene in Step Brothers when they ask if they can build the bunk beds. I don’t know how many more times I can say the fight is off or how many more press conferences I can have saying the fight is off for people to believe it’s off.”

The restoration of McGregor to the card would enable him to avenge his second-round submission loss to Nate Diaz from last month. McGregor, the 145-pound champion, again strangely seeks to fight at 170 pounds against Diaz. But, like White, Diaz says the fight is off.

“There had been 10 million dollars allocated for the promotion of this event is what they told me,” McGregor said in response to the UFC originally pulling him from the fight. “So as a gesture of good will, I went and not only saved that 10 million dollars in promotion money, I then went and tripled it for them. And all with one tweet.”

The featherweight champion’s “thanks for the cheese” retirement tweet shattered the record number of re-tweets Kobe Bryant’s “Dear Basketball” retirement tweet received last year.

The Irishman had rationalized bucking press conferences in the United States for training in Iceland by saying, “There comes a time when you need to stop handing out flyers and get back to the damn shop.”

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